[MUD-Dev] Source data on Crossbow

[Ben Tolputt]

From: Bobby Martin - Tuesday, February 05, 2002 04:26 AM

> In fact, since momentum (mass * velocity) is conserved as well as
> energy, it doesn't matter at all how much resistance the target
> has.  If the bullet hits the target and no chunks go flying off,
> then all of the momentum of the bullet is transfered into the
> target.  So the velocity of the target changes by a set amount

> delta v of target = velocity of bullet * mass of bullet / (mass of
> target + mass of bullet)

> No matter how much energy is dissipated as internal damage, noise,
> heat, etc.

> Conservation of energy is not very important in determining how
> much the target will move; conservation of momentum, on what part
> of the target the collision takes place, and biological factors
> (muscles going limp, etc.) are much more important.

Actually conservation of momentum CAN be negated by engery coming
off as noise,heat, etc. If that were not true you would get MORE
energy out than you put in. Though you are correct in that unless
big chunks come off the impact MOST of the energy will still go into
momentum conservation.


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